Originally Answered: What is the probability of getting at least one 4 when you throw 2 dices? Getting 4 in one is 1/6 and in second is again 1/6. Probability of getting 4 in both is 1/36.

## What is the probability of rolling at least a 4?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

2 | 1/36 (2.778%) |

3 | 3/36 (8.333%) |

4 | 6/36 (16.667%) |

5 | 10/36 (27.778%) |

## What is the probability of rolling a sum of 4 with two dice?

Probability of getting a sum of 4 on one toss of two dice is **3/36**, or 1/12.

## What is the probability of rolling at least one 5 with two dice?

Probability of outcome numbers >5 on two dice = **1/36**, Ans. I hope it helps you…!!! There are four ways to roll a five, three ways to get four, two ways to get three, and one way to get two. So 26 out of 36 possible rolls are over 5, or 72.2%.

## What is the probability of rolling at least one 4 on the three dice?

Outcomes containing at least one occurrence of 4 when rolling 3 dice: Therefore, **91 of** the 216 possible 3 dice roll outcomes contain at least one (4).

## What is the probability of not rolling any 6’s in four rolls of a balanced die?

a) Consider the complement problem, there is a 5/6 probability of not rolling a six for any given die, and since the four dice are independent, the probability of not rolling a six is (5/6)4 = 54/64 = **625/1296**.

## What is the probability of getting a sum of 4 dice?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

3 | 2 | 5.56% |

4 | 3 | 8.33% |

5 | 4 |
11.11% |

6 | 5 | 13.89% |

## What is the probability of getting a total of 7 when rolling two dice?

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is **6/36 = 1/6**.

## How do you find the probability of at least?

To find the probability of at least one of something, calculate **the probability of none and then subtract that result from 1**. That is, P(at least one) = 1 – P(none).

## What is the probability of rolling a 1 or a 5 on a die?

Thats (4/6)2. Hence the probability that at least one shows a 1 or 5 is 1−(2/3)2=**5/9**.